author: niplav, created: 2022-01-25, modified: 2023-04-19, language: english, status: in progress, importance: 1, confidence: log
;-)
The fitness contribution of each of the
$\hat{n}$heterozygous loci to the parthenogenetic individual's overall fitness is$1+hs$. If the overall fitness of an individual is the product of the fitnesses of individual loci (multiplicative epistasis), then the total fitness contribution of the$\hat{n}$heterozygous loci is$(1+hs)^{\hat{n}}$. These same loci in the sexual species will have sped to fixation, so their total fitness contribution is$(1+s)^{\hat{n}}$. The relative advantage of the sexual species is$$W_s=\left (\frac{1+s}{1+hs}\right )^{\hat{n}}$$
— John H. Gillespie, “Population Genetics” p. 172, 2004